Answer by barbwire for XSLT: get relative URI instead of absolute uri
Could this work: <xsl:value-of select="replace(base-uri(), $folderURI, '') "/>(did not see this at the comments), since if the problem is the absolute path at the xref, replacing the path with...
View ArticleXSLT: get relative URI instead of absolute uri
I want to:Create a file in the same folder where I am running my XSLT stylesheet against.This new file has a list of href to files with a certain value in the copyrholder element.Have a relative path...
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